Diketahui log 2=0,301 dan log 3=0,477 hitunglah nilai dari a. log 12 b. log 12

log 12
= log2*2*3
= log 2 + log 2 + log 3
= 0,301 + 0,301 + 0,477
= 0,602 + 0,477
= 1,079

a) log 12
=> log (4x3)
=> log 4 + log 3
=> log 2^2 + 0,477
=> 2 log2 + 0,477
=> 2(0,301) + 0,477
=> 0,602 + 0,477
=> 1,079

b) sama