Fisika

Pertanyaan

1-3 tlong

beserta rumus
1-3 tlong beserta rumus

2 Jawaban

  • 1.km=l/h
    =9/3
    =3
    Fk=Fb/km
    =750/3
    =250 N
    2.km=Lk/Lb
    =4/2
    =2
    gaya=beban/km
    =3000/2
    =1500 N
    3.Lb=1 Lk=5 km=5/1=5
    gaya=3000/5
    =600 N
  • No. 1
    --------
    Diket :
    Berat lemari, W = 750 N
    Tinggi loteng, h = 3 m
    Panjang bidang miring, s = 9 m

    Tanya :
    Gaya kuasa, F = __?

    Jawab :
    F = (h/s).W
    F = (3/9)•750
    F = (1/3)•750
    F = 250 N

    No.2
    -------
    Diket :
    Berat beban, W = 3000 N
    Panjang lengan beban, Lw = 2 m
    Panah lengan gaya, Lf = 4 m

    Tanya ;
    Gaya kuasa, F = __?

    Jawab :

    F = (Lw/Lf).w
    F = (2/4)•3000
    F = (1/2)•3000
    F = 1500 N

    No. 3
    --------
    Diket :
    Berat beban, W = 3000 N
    Panjang tuas, L = 6 m
    Pangang lengan beban, Lw = 1 m

    Tanya :
    Gaya kuasa, F = __?

    Jawab :
    Step 1
    ---------
    Cari dulu panjang lengan kuasa yak,

    Lf + Lw = L
    Lf + 1 = 6
    Lf = 5 m

    Step 2
    ---------
    F = (Lw/Lf).w
    F = (1/5)• 3000
    F = 600 N

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    FZA