Cobalah memfaktorkan dengan melengkapi soal soal berikut. 1. 6y² + 7y + 2 = 6y² + (__ + __) + 2 = (6y² + __) + (__ + 2) = 3y(__ + __) + 2(__ + __) = (3y + 2)
Matematika
wswquggjhwehjvg
Pertanyaan
Cobalah memfaktorkan dengan melengkapi soal soal berikut.
1. 6y² + 7y + 2 = 6y² + (__ + __) + 2
= (6y² + __) + (__ + 2)
= 3y(__ + __) + 2(__ + __)
= (3y + 2) (__ + __)
2. 2z² - 5z + 2 = 2z² - (__ + __) + 2
= 2z² - __ - __ + 2
= (2z² - __) - (__ - 2)
= __ (z - 2) - (__ - 2)
= (__ - __) (z - 2)
1. 6y² + 7y + 2 = 6y² + (__ + __) + 2
= (6y² + __) + (__ + 2)
= 3y(__ + __) + 2(__ + __)
= (3y + 2) (__ + __)
2. 2z² - 5z + 2 = 2z² - (__ + __) + 2
= 2z² - __ - __ + 2
= (2z² - __) - (__ - 2)
= __ (z - 2) - (__ - 2)
= (__ - __) (z - 2)
1 Jawaban
-
1. Jawaban Jellyeen
1. 6y² + 7y + 2 = 6y² + (3y+ 4y) + 2
= (6y² + 3y) + (4y + 2)
= 3y(2y+ 1) + 2(2y+ 1)
= (3y + 2) (2y+ 1)
2. 2z² - 5z + 2 = 2z² - (4z+ z)+ 2
= 2z² - 4z - z+ 2
= (2z² - 4) - (z - 2)
= 2z(z - 2) - (z - 2)
= (2z - 1) (z - 2)