jika sin 105= P maka nilai P-1/4√6=...

sin 105=p
=sin (60+45)=p
=sin60.cos45+cos60.sin45=p
=1/2akar3.1/2akar2+1/2.1/2akar2=p
=1/4akar6+1/4akar2=p

jadi,
p-1/4akar6
=1/4akar6+1/4akar2-1/4akar6
=1/4akar2

maaf kalau salah