Matematika

Pertanyaan

a. 295 kelvin brp reamur , farenheit,celcius
B.194 farenheit brp kelvin , reamur,celcius
C.95 celcius brp reamur farenheit kelvin
D.65 reamur brp farenheit , kelvin , celcius
E.303 kelvin brp celcius , farenheit , reamur

Langsung jawaban aja . Thanks

1 Jawaban

  • C : R : F : K
    5 : 4 : 9 : 5

    a. 295 - 273 = 22 ° C
    4/ 5 x 22 =88 : 5
    =17,6 ° R
    9/ 5 x 22 = 198 : 5
    = 39,6 + 32 =71,6 °F

    b. 194 + 273 = 467 Kelvin
    194-32= 162
    162 : 9 =18
    5/9 x 162 = 18 x 5 = 85° C
    4/ 9 x 162 = 18 x 4 = 72°R

    c. 95 + 273 = 368 Kelvin
    4/ 5 x 95 = 19 x 4
    = 76° R
    9/ 5 x 95 = 19 x 9
    =171 + 32 = 203 ° F

    d. 65 + 273 = 338 Kelvin
    5/4 x 65 = 325 : 4
    = 81,25° C
    9/ 4 x 65 = 585 : 4
    = 146,25 + 32 =178 ° F

    e. 303 - 273 =30 ° C
    4/5 x 30 = 4 x 6
    = 24 ° R
    9/ 5 x 30= 9 x 6
    54 + 32 = 86 ° F

    Kalo ada yang salah maafkan :v


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