yg no 13& 14 bagaimana caranya

13)
f(x) = 4^(x) + 3.2^(x+2) = 64
f(x) = (2^2)^(x) + 3.2^(x+2) - 64 = 0
f(x) = 2^(2x) + 3.2^(x+2) - 64 = 0
f(x) = 2^(2x) + 3.2^(2).2^(x) - 64 = 0
f(x) = 2^(2x) + 3.4.2^(x) - 64 = 0
f(x) = 2^(2x) + 12.2^(x) - 64 = 0

Misal : a = 2^(x)

a^2 + 12a - 64 = 0
(a + 16)(a - 4) = 0
a + 16 = 0 atau a - 4 = 0
a = -16 atau a = 4

a = 2^(x)
a = -16
2^(x) = -2^4
(Tidak memenuhi)

a = 2^(x)
a = 4
2^(x) = 4
2^(x) = 2^2
x = 2

HP = { 2 } (c)

14)
2^(2x+5) = 2^(3x+1)

2x + 5 = 3x + 1
2x - 3x = 1 - 5
-x = -4
x = -4/-1
x = 4

HPnya = { 4 } (e)