Matematika

Pertanyaan

Pada persamaan x²+2x-15=0,tentukan nilai akar-akar berikut
a.x1+x2
b.x1×x2
c.4x1+5x2
d.3x1×4x2

1 Jawaban

  • Bab Persamaan Kuadrat

    X^2+2x-15 = 0
    (x+5)(x-3) = 0

    X1 =-5
    X2 = 3


    a.X1 + X2 = (-5) + 3 = -2

    b.X1 × X2 = (-5) × 3 = -15

    c.4X 1 + 5X 2 = 4(-5) + 5(3) = -20 + 15 = -5

    d.3X 1 + 4x 2 = 3(-5) + 4(3) = -15 + 12 = -3

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