tentukan nilai x,y,z dari sistem persamaan linear tiga variable berikut : 2x-y+z=5 x-2y+3z=9 x+3y+z=0

2x - y + z = 5 ---(1)
x - 2y + 3z = 9 ---(2)
x + 3y + z = 0 ---(3)
[Jawab]
(1) × 2 = 4x - 2y + 2z = 10 ---(1)'
(2) - (1)' = -3x + z = -1 ---(4)
(2) × 3 = 3x - 6y + 9z = 27 ---(2)'
(3) × 2 = 2x + 6y + 2z = 0 ---(3)'
--------------------------- +
5x + 11z = 27 ---(5)
(4) × 11 = - 33x + 11z = - 11 ---(4)'
-------------------------- -
38 x = 38
x = 1
Masukan ke (4)
-3 + z = -1
z = - 1 + 3
z = 2
Masukan x = 1 & z = 2 ke (1)
2 - y + 2 = 5
- y = 5 - 2 -2
- y = 1
y = - 1
Jadi,(x,y,z) = ( 1, -1, 2 )
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Maaf kalo jawabnya salah