tentukan HP dari 4^2x-1 = 128

[tex]4 x^{2} -1=128 \\ 4 x^{2} =128+1 \\ 4 x^{2} =129 \\ x^{2} = \frac{129}{4} \\ x=+ /- \sqrt{129} \\ HP={x|x=+/- \sqrt{129, x∈R } [/tex]

4^2x - 1 = 128
2^2(2x-1) = 2^7
2(2x-1) = 7
4x -2 = 7
4x = 7 +2
4x = 9
x = 9/4
x = 2 1/4

Hp = {2 1/4)