Matematika

Pertanyaan

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log 2 + log 200 - log 6 + log 5 - log 3 + log 18 - log 2

1 Jawaban

  • Bab Logaritma
    Matematika SMA Kelas X

    log 2 + log 200 - log 6 + log 5 - log 3 + log 18 - log 2
    = log (2 x 200 : 6 x 5 : 3 x 18 : 2)
    = log ((2 x 200 x 5 x 18) : (6 x 3 x 2))
    = log (36.000 : 36)
    = log 1.000
    = 3

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