Jika log 2=0,301 dan log 3=0,477,log 5=0,699 tentukan log 288
Matematika
oliviarahmawati
Pertanyaan
Jika log 2=0,301 dan log 3=0,477,log 5=0,699 tentukan log 288
1 Jawaban
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1. Jawaban danualimfigianto
288 = 2.2.2.2.2.3.3
log288=log(2.2.2.2.2.3.3)
=4 x log 2 + 2 x log 3
=4 x 0.301 + 2 x 0.477
=1,204 + 0.954
=2,158